13x^2-196=0

Solution for 13x^2-196=0 equation:

13x^2-196=0

a = 13; b = 0; c = -196;
Δ = b2-4ac
Δ = 02-4·13·(-196)
Δ = 10192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10192}=\sqrt{784*13}=\sqrt{784}*\sqrt{13}=28\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{13}}{2*13}=\frac{0-28\sqrt{13}}{26}
=-\frac{28\sqrt{13}}{26}
=-\frac{14\sqrt{13}}{13}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{13}}{2*13}=\frac{0+28\sqrt{13}}{26}
=\frac{28\sqrt{13}}{26}
=\frac{14\sqrt{13}}{13}
$